6(-8x-4)=8(-4x-7)-8x

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Solution for 6(-8x-4)=8(-4x-7)-8x equation: 



6(-8x-4)=8(-4x-7)-8x

We move all terms to the left:

6(-8x-4)-(8(-4x-7)-8x)=0

We multiply parentheses

-48x-(8(-4x-7)-8x)-24=0



We calculate terms in parentheses: -(8(-4x-7)-8x), so:

8(-4x-7)-8x

We add all the numbers together, and all the variables

-8x+8(-4x-7)

We multiply parentheses

-8x-32x-56

We add all the numbers together, and all the variables

-40x-56

Back to the equation:

-(-40x-56)



We get rid of parentheses

-48x+40x+56-24=0

We add all the numbers together, and all the variables

-8x+32=0

We move all terms containing x to the left, all other terms to the right

-8x=-32

x=-32/-8

x=+4

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