4(x+1)=3(x-3)=2

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Solution for 4(x+1)=3(x-3)=2 equation: 



4(x+1)=3(x-3)=2

We move all terms to the left:

4(x+1)-(3(x-3))=0

We multiply parentheses

4x-(3(x-3))+4=0



We calculate terms in parentheses: -(3(x-3)), so:

3(x-3)

We multiply parentheses

3x-9

Back to the equation:

-(3x-9)



We get rid of parentheses

4x-3x+9+4=0

We add all the numbers together, and all the variables

x+13=0

We move all terms containing x to the left, all other terms to the right

x=-13

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