3(a+11)=6(a+33)

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Solution for 3(a+11)=6(a+33) equation: 



3(a+11)=6(a+33)

We move all terms to the left:

3(a+11)-(6(a+33))=0

We multiply parentheses

3a-(6(a+33))+33=0



We calculate terms in parentheses: -(6(a+33)), so:

6(a+33)

We multiply parentheses

6a+198

Back to the equation:

-(6a+198)



We get rid of parentheses

3a-6a-198+33=0

We add all the numbers together, and all the variables

-3a-165=0

We move all terms containing a to the left, all other terms to the right

-3a=165

a=165/-3

a=-55

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