7k-12=3(6-k)

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Solution for 7k-12=3(6-k) equation: 



7k-12=3(6-k)

We move all terms to the left:

7k-12-(3(6-k))=0

We add all the numbers together, and all the variables

7k-(3(-1k+6))-12=0



We calculate terms in parentheses: -(3(-1k+6)), so:

3(-1k+6)

We multiply parentheses

-3k+18

Back to the equation:

-(-3k+18)



We get rid of parentheses

7k+3k-18-12=0

We add all the numbers together, and all the variables

10k-30=0

We move all terms containing k to the left, all other terms to the right

10k=30

k=30/10

k=3

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