If it's not what You are looking for type in the equation solver your own equation and let us solve it.
k+5/2=10
We move all terms to the left:
k+5/2-(10)=0
determiningTheFunctionDomain k-10+5/2=0
We multiply all the terms by the denominator
k*2+5-10*2=0
We add all the numbers together, and all the variables
k*2-15=0
Wy multiply elements
2k-15=0
We move all terms containing k to the left, all other terms to the right
2k=15
k=15/2
k=7+1/2
| 12x-15=3(2x+3)=4 | | 4-7j=1-6j | | -4x-3=-1x-30 | | -4h-3=-6h+9 | | 5-2t=3t=1 | | 2+3x=2+2x | | 4(f+2)=2f-10 | | 2x-5=-1x+19 | | (85)+4=9x5 | | -7x+13=24+12x | | 5-3x=-5-3x | | −7x+13=24−12x | | 2x^-15=65 | | 1.5x+4=-1.66x+-2.33 | | 13+a=17 | | (z+9)/2=-3 | | 7k=-105 | | 6d+7=8d-13 | | 7+4(2-x)-2x=8+3x | | -19-x=-18x+-36 | | .6=1−2n+5 | | 2n=n-7 | | 4k+5=3k | | 3x+8=x-3 | | m=3A(-1;7) | | (2x+1)=(x+4) | | 2x+12=9x-9=6x+3 | | X+7=3x+1=2x+5 | | 5x+8(2x-8)=54 | | 7x-12=8x+29-2 | | 34=8x-6=50 | | -u+7/4=-1/4u-2/3 |