3(k-5)=2k+6

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Solution for 3(k-5)=2k+6 equation: 



3(k-5)=2k+6

We move all terms to the left:

3(k-5)-(2k+6)=0

We multiply parentheses

3k-(2k+6)-15=0

We get rid of parentheses

3k-2k-6-15=0

We add all the numbers together, and all the variables

k-21=0

We move all terms containing k to the left, all other terms to the right

k=21

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