4(d-2)+5=3(2d-1)-2d

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Solution for 4(d-2)+5=3(2d-1)-2d equation: 



4(d-2)+5=3(2d-1)-2d

We move all terms to the left:

4(d-2)+5-(3(2d-1)-2d)=0

We multiply parentheses

4d-(3(2d-1)-2d)-8+5=0



We calculate terms in parentheses: -(3(2d-1)-2d), so:

3(2d-1)-2d

We add all the numbers together, and all the variables

-2d+3(2d-1)

We multiply parentheses

-2d+6d-3

We add all the numbers together, and all the variables

4d-3

Back to the equation:

-(4d-3)



We add all the numbers together, and all the variables

4d-(4d-3)-3=0

We get rid of parentheses

4d-4d+3-3=0

We add all the numbers together, and all the variables

=0

d=0/1

d=0

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