132=4(5n+3)

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Solution for 132=4(5n+3) equation: 



132=4(5n+3)

We move all terms to the left:

132-(4(5n+3))=0



We calculate terms in parentheses: -(4(5n+3)), so:

4(5n+3)

We multiply parentheses

20n+12

Back to the equation:

-(20n+12)



We get rid of parentheses

-20n-12+132=0

We add all the numbers together, and all the variables

-20n+120=0

We move all terms containing n to the left, all other terms to the right

-20n=-120

n=-120/-20

n=+6

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