Y+1-2(-3y-1)=3(y-5)

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Solution for Y+1-2(-3y-1)=3(y-5) equation: 



+1-2(-3Y-1)=3(Y-5)

We move all terms to the left:

+1-2(-3Y-1)-(3(Y-5))=0

We multiply parentheses

6Y-(3(Y-5))+2+1=0



We calculate terms in parentheses: -(3(Y-5)), so:

3(Y-5)

We multiply parentheses

3Y-15

Back to the equation:

-(3Y-15)



We add all the numbers together, and all the variables

6Y-(3Y-15)+3=0

We get rid of parentheses

6Y-3Y+15+3=0

We add all the numbers together, and all the variables

3Y+18=0

We move all terms containing Y to the left, all other terms to the right

3Y=-18

Y=-18/3

Y=-6

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