4(c-3)+6=10

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Solution for 4(c-3)+6=10 equation:



4(c-3)+6=10
We move all terms to the left:
4(c-3)+6-(10)=0
We add all the numbers together, and all the variables
4(c-3)-4=0
We multiply parentheses
4c-12-4=0
We add all the numbers together, and all the variables
4c-16=0
We move all terms containing c to the left, all other terms to the right
4c=16
c=16/4
c=4

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