(X+3)(x-1)=650

Solution for (X+3)(x-1)=650 equation:

(X+3)(X-1)=650

We move all terms to the left:

(X+3)(X-1)-(650)=0

We multiply parentheses ..

(+X^2-1X+3X-3)-650=0

We get rid of parentheses

X^2-1X+3X-3-650=0

We add all the numbers together, and all the variables

X^2+2X-653=0

a = 1; b = 2; c = -653;
Δ = b2-4ac
Δ = 22-4·1·(-653)
Δ = 2616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2616}=\sqrt{4*654}=\sqrt{4}*\sqrt{654}=2\sqrt{654}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{654}}{2*1}=\frac{-2-2\sqrt{654}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{654}}{2*1}=\frac{-2+2\sqrt{654}}{2}
$