4(4)=3(2b-15)

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Solution for 4(4)=3(2b-15) equation: 



4(4)=3(2b-15)

We move all terms to the left:

4(4)-(3(2b-15))=0



We calculate terms in parentheses: -(3(2b-15)), so:

3(2b-15)

We multiply parentheses

6b-45

Back to the equation:

-(6b-45)



We get rid of parentheses

-6b+45+44=0

We add all the numbers together, and all the variables

-6b+89=0

We move all terms containing b to the left, all other terms to the right

-6b=-89

b=-89/-6

b=14+5/6

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