3x2-16x-187=0

Solution for 3x2-16x-187=0 equation:

3x^2-16x-187=0

a = 3; b = -16; c = -187;
Δ = b2-4ac
Δ = -162-4·3·(-187)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-50}{2*3}=\frac{-34}{6}
=-5+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+50}{2*3}=\frac{66}{6}
=11
$