3*((276-3x)/3)+3x=276

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Solution for 3*((276-3x)/3)+3x=276 equation: 



3((276-3x)/3)+3x=276

We move all terms to the left:

3((276-3x)/3)+3x-(276)=0

We add all the numbers together, and all the variables

3((-3x+276)/3)+3x-276=0

We add all the numbers together, and all the variables

3x+3((-3x+276)/3)-276=0

We multiply all the terms by the denominator


3x*3)+3((-3x+276)-276*3)=0

We add all the numbers together, and all the variables

3x*3)+3((-3x+276)=0

Wy multiply elements

9x^2=0

a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{18}=0$

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