(3-x)*(3+x)=x*(4-x)

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Solution for (3-x)*(3+x)=x*(4-x) equation: 



(3-x)(3+x)=x(4-x)

We move all terms to the left:

(3-x)(3+x)-(x(4-x))=0

We add all the numbers together, and all the variables

(-1x+3)(x+3)-(x(-1x+4))=0

We multiply parentheses ..

(-1x^2-3x+3x+9)-(x(-1x+4))=0



We calculate terms in parentheses: -(x(-1x+4)), so:

x(-1x+4)

We multiply parentheses

-1x^2+4x

Back to the equation:

-(-1x^2+4x)



We get rid of parentheses

-1x^2+1x^2-3x+3x-4x+9=0

We add all the numbers together, and all the variables

-4x+9=0

We move all terms containing x to the left, all other terms to the right

-4x=-9

x=-9/-4

x=2+1/4

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