1/x+1/(x+3)=1/4

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Solution for 1/x+1/(x+3)=1/4 equation: 



1/x+1/(x+3)=1/4

We move all terms to the left:

1/x+1/(x+3)-(1/4)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x+3)!=0

We move all terms containing x to the left, all other terms to the right

x!=-3

x∈R



We add all the numbers together, and all the variables

1/x+1/(x+3)-(+1/4)=0

We get rid of parentheses

1/x+1/(x+3)-1/4=0

We calculate fractions


(-1x^2*()/(4x^2+12x)+(4x+12)/(4x^2+12x)+16x/(4x^2+12x)=0



We calculate terms in parentheses: +(-1x^2*()/(4x^2+12x)+(4x+12)/(4x^2+12x)+16x/(4x^2+12x), so:

-1x^2*()/(4x^2+12x)+(4x+12)/(4x^2+12x)+16x/(4x^2+12x

We calculate fractions

We do not support expression: x^3

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