8(4x+x)=64

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Solution for 8(4x+x)=64 equation: 



8(4x+x)=64

We move all terms to the left:

8(4x+x)-(64)=0

We add all the numbers together, and all the variables

8(+5x)-64=0

We multiply parentheses

40x-64=0

We move all terms containing x to the left, all other terms to the right

40x=64

x=64/40

x=1+3/5

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