3a-3a=3(-1-a)-(a+3)

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Solution for 3a-3a=3(-1-a)-(a+3) equation: 



3a-3a=3(-1-a)-(a+3)

We move all terms to the left:

3a-3a-(3(-1-a)-(a+3))=0

We add all the numbers together, and all the variables

3a-3a-(3(-1a-1)-(a+3))=0

We add all the numbers together, and all the variables

-(3(-1a-1)-(a+3))=0



We calculate terms in parentheses: -(3(-1a-1)-(a+3)), so:

3(-1a-1)-(a+3)

We multiply parentheses

-3a-(a+3)-3

We get rid of parentheses

-3a-a-3-3

We add all the numbers together, and all the variables

-4a-6

Back to the equation:

-(-4a-6)



We get rid of parentheses

4a+6=0

We move all terms containing a to the left, all other terms to the right

4a=-6

a=-6/4

a=-1+1/2

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