2x-2-3x(x+2)=8-4x

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Solution for 2x-2-3x(x+2)=8-4x equation: 



2x-2-3x(x+2)=8-4x

We move all terms to the left:

2x-2-3x(x+2)-(8-4x)=0

We add all the numbers together, and all the variables

2x-3x(x+2)-(-4x+8)-2=0

We multiply parentheses

-3x^2+2x-6x-(-4x+8)-2=0

We get rid of parentheses

-3x^2+2x-6x+4x-8-2=0

We add all the numbers together, and all the variables

-3x^2-10=0

a = -3; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·(-3)·(-10)
Δ = -120
Delta is less than zero, so there is no solution for the equation

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