(1/3)k-2=-6

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Solution for (1/3)k-2=-6 equation: 



(1/3)k-2=-6

We move all terms to the left:

(1/3)k-2-(-6)=0



Domain of the equation: 3)k!=0

k!=0/1

k!=0

k∈R



We add all the numbers together, and all the variables

(+1/3)k-2-(-6)=0

We add all the numbers together, and all the variables

(+1/3)k+4=0

We multiply parentheses

k^2+4=0

a = 1; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·1·4
Δ = -16
Delta is less than zero, so there is no solution for the equation

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