3y-5=7(y+1)

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Solution for 3y-5=7(y+1) equation: 



3y-5=7(y+1)

We move all terms to the left:

3y-5-(7(y+1))=0



We calculate terms in parentheses: -(7(y+1)), so:

7(y+1)

We multiply parentheses

7y+7

Back to the equation:

-(7y+7)



We get rid of parentheses

3y-7y-7-5=0

We add all the numbers together, and all the variables

-4y-12=0

We move all terms containing y to the left, all other terms to the right

-4y=12

y=12/-4

y=-3

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