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3x(2x-7)=2x*x-16-5x
We move all terms to the left:
3x(2x-7)-(2x*x-16-5x)=0
We add all the numbers together, and all the variables
3x(2x-7)-(-5x+2x*x-16)=0
We multiply parentheses
6x^2-21x-(-5x+2x*x-16)=0
We get rid of parentheses
6x^2-21x+5x-2x*x+16=0
We add all the numbers together, and all the variables
6x^2-16x-2x*x+16=0
Wy multiply elements
6x^2-2x^2-16x+16=0
We add all the numbers together, and all the variables
4x^2-16x+16=0
a = 4; b = -16; c = +16;
Δ = b2-4ac
Δ = -162-4·4·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{16}{8}=2$
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