x2+2x-(168)=(x+14)(x-12)

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Solution for x2+2x-(168)=(x+14)(x-12) equation: 



x2+2x-(168)=(x+14)(x-12)

We move all terms to the left:

x2+2x-(168)-((x+14)(x-12))=0

We add all the numbers together, and all the variables

x^2+2x-((x+14)(x-12))-168=0

We multiply parentheses ..

x^2-((+x^2-12x+14x-168))+2x-168=0



We calculate terms in parentheses: -((+x^2-12x+14x-168)), so:

(+x^2-12x+14x-168)

We get rid of parentheses

x^2-12x+14x-168

We add all the numbers together, and all the variables

x^2+2x-168

Back to the equation:

-(x^2+2x-168)



We add all the numbers together, and all the variables

x^2+2x-(x^2+2x-168)-168=0

We get rid of parentheses

x^2-x^2+2x-2x+168-168=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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