3(x-3)-14=2(x-8)+10

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Solution for 3(x-3)-14=2(x-8)+10 equation: 



3(x-3)-14=2(x-8)+10

We move all terms to the left:

3(x-3)-14-(2(x-8)+10)=0

We multiply parentheses

3x-(2(x-8)+10)-9-14=0



We calculate terms in parentheses: -(2(x-8)+10), so:

2(x-8)+10

We multiply parentheses

2x-16+10

We add all the numbers together, and all the variables

2x-6

Back to the equation:

-(2x-6)



We add all the numbers together, and all the variables

3x-(2x-6)-23=0

We get rid of parentheses

3x-2x+6-23=0

We add all the numbers together, and all the variables

x-17=0

We move all terms containing x to the left, all other terms to the right

x=17

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