2(2z-3)=9(z+4)

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Solution for 2(2z-3)=9(z+4) equation: 



2(2z-3)=9(z+4)

We move all terms to the left:

2(2z-3)-(9(z+4))=0

We multiply parentheses

4z-(9(z+4))-6=0



We calculate terms in parentheses: -(9(z+4)), so:

9(z+4)

We multiply parentheses

9z+36

Back to the equation:

-(9z+36)



We get rid of parentheses

4z-9z-36-6=0

We add all the numbers together, and all the variables

-5z-42=0

We move all terms containing z to the left, all other terms to the right

-5z=42

z=42/-5

z=-8+2/5

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