5(i+2)-9=-27-i

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Solution for 5(i+2)-9=-27-i equation: 



5(i+2)-9=-27-i

We move all terms to the left:

5(i+2)-9-(-27-i)=0

We add all the numbers together, and all the variables

5(i+2)-(-1i-27)-9=0

We multiply parentheses

5i-(-1i-27)+10-9=0

We get rid of parentheses

5i+1i+27+10-9=0

We add all the numbers together, and all the variables

6i+28=0

We move all terms containing i to the left, all other terms to the right

6i=-28

i=-28/6

i=-4+2/3

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