F=2(4x+5)6x

Solution for F=2(4x+5)6x equation:

=2(4F+5)6F

We move all terms to the left:

-(2(4F+5)6F)=0


We calculate terms in parentheses: -(2(4F+5)6F), so:

2(4F+5)6F

We multiply parentheses

48F^2+60F

Back to the equation:

-(48F^2+60F)


We get rid of parentheses

-48F^2-60F=0

a = -48; b = -60; c = 0;
Δ = b2-4ac
Δ = -602-4·(-48)·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-60}{2*-48}=\frac{0}{-96}
=0
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+60}{2*-48}=\frac{120}{-96}
=-1+1/4
$