3(2x-5)-4=18-2(6-3x)x=

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Solution for 3(2x-5)-4=18-2(6-3x)x= equation: 



3(2x-5)-4=18-2(6-3x)x=

We move all terms to the left:

3(2x-5)-4-(18-2(6-3x)x)=0

We add all the numbers together, and all the variables

3(2x-5)-(18-2(-3x+6)x)-4=0

We multiply parentheses

6x-(18-2(-3x+6)x)-15-4=0



We calculate terms in parentheses: -(18-2(-3x+6)x), so:

18-2(-3x+6)x

determiningTheFunctionDomain
-2(-3x+6)x+18

We multiply parentheses

6x^2-12x+18

Back to the equation:

-(6x^2-12x+18)



We add all the numbers together, and all the variables

6x-(6x^2-12x+18)-19=0

We get rid of parentheses

-6x^2+6x+12x-18-19=0

We add all the numbers together, and all the variables

-6x^2+18x-37=0

a = -6; b = 18; c = -37;
Δ = b2-4ac
Δ = 182-4·(-6)·(-37)
Δ = -564
Delta is less than zero, so there is no solution for the equation

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