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3(x-2)+2(2x+5)-1=32
We move all terms to the left:
3(x-2)+2(2x+5)-1-(32)=0
We add all the numbers together, and all the variables
3(x-2)+2(2x+5)-33=0
We multiply parentheses
3x+4x-6+10-33=0
We add all the numbers together, and all the variables
7x-29=0
We move all terms containing x to the left, all other terms to the right
7x=29
x=29/7
x=4+1/7
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