3(x-2)-(x-1)=7(x-1)-6(x-2)

Solution for 3(x-2)-(x-1)=7(x-1)-6(x-2) equation:

3(x-2)-(x-1)=7(x-1)-6(x-2)

We move all terms to the left:

3(x-2)-(x-1)-(7(x-1)-6(x-2))=0

We multiply parentheses

3x-(x-1)-(7(x-1)-6(x-2))-6=0

We get rid of parentheses

3x-x-(7(x-1)-6(x-2))+1-6=0


We calculate terms in parentheses: -(7(x-1)-6(x-2)), so:

7(x-1)-6(x-2)

We multiply parentheses

7x-6x-7+12

We add all the numbers together, and all the variables

x+5

Back to the equation:

-(x+5)


We add all the numbers together, and all the variables

2x-(x+5)-5=0

We get rid of parentheses

2x-x-5-5=0

We add all the numbers together, and all the variables

x-10=0

We move all terms containing x to the left, all other terms to the right

x=10