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-1=-x(5x+3)
We move all terms to the left:
-1-(-x(5x+3))=0
We calculate terms in parentheses: -(-x(5x+3)), so:We get rid of parentheses
-x(5x+3)
We multiply parentheses
-5x^2-3x
Back to the equation:
-(-5x^2-3x)
5x^2+3x-1=0
a = 5; b = 3; c = -1;
Δ = b2-4ac
Δ = 32-4·5·(-1)
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{29}}{2*5}=\frac{-3-\sqrt{29}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{29}}{2*5}=\frac{-3+\sqrt{29}}{10} $
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