3(x-5)=7(2x+3)-4(x-2)-5(x-2)=

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Solution for 3(x-5)=7(2x+3)-4(x-2)-5(x-2)= equation: 



3(x-5)=7(2x+3)-4(x-2)-5(x-2)=

We move all terms to the left:

3(x-5)-(7(2x+3)-4(x-2)-5(x-2))=0

We multiply parentheses

3x-(7(2x+3)-4(x-2)-5(x-2))-15=0



We calculate terms in parentheses: -(7(2x+3)-4(x-2)-5(x-2)), so:

7(2x+3)-4(x-2)-5(x-2)

We multiply parentheses

14x-4x-5x+21+8+10

We add all the numbers together, and all the variables

5x+39

Back to the equation:

-(5x+39)



We get rid of parentheses

3x-5x-39-15=0

We add all the numbers together, and all the variables

-2x-54=0

We move all terms containing x to the left, all other terms to the right

-2x=54

x=54/-2

x=-27

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