9.3/x=(3-x)/2.7

Solution for 9.3/x=(3-x)/2.7 equation:

9.3/x=(3-x)/2.7

We move all terms to the left:

9.3/x-((3-x)/2.7)=0


Domain of the equation: x!=0

x∈R


We add all the numbers together, and all the variables

9.3/x-((-1x+3)/2.7)=0

We calculate fractions


()/2x^2+(-((-1x+3)*x)/2x^2=0

We multiply all the terms by the denominator


(-((-1x+3)*x)+()=0


We calculate terms in parentheses: +(-((-1x+3)*x)+(), so:

-((-1x+3)*x)+(

We add all the numbers together, and all the variables

-((-1x+3)*x)


We calculate terms in parentheses: -((-1x+3)*x), so:

(-1x+3)*x

We multiply parentheses

-1x^2+3x

Back to the equation:

-(-1x^2+3x)


We get rid of parentheses

1x^2-3x

We add all the numbers together, and all the variables

x^2-3x

Back to the equation:

+(x^2-3x)


We get rid of parentheses

x^2-3x=0

a = 1; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·1·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*1}=\frac{0}{2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*1}=\frac{6}{2}
=3
$