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(x-9)(x=6)
We move all terms to the left:
(x-9)(x-(6))=0
We multiply parentheses ..
(+x^2-6x-9x+54)=0
We get rid of parentheses
x^2-6x-9x+54=0
We add all the numbers together, and all the variables
x^2-15x+54=0
a = 1; b = -15; c = +54;
Δ = b2-4ac
Δ = -152-4·1·54
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-3}{2*1}=\frac{12}{2} =6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+3}{2*1}=\frac{18}{2} =9 $
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