3(3x-4)-21x=7(4x-27)-63

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Solution for 3(3x-4)-21x=7(4x-27)-63 equation: 



3(3x-4)-21x=7(4x-27)-63

We move all terms to the left:

3(3x-4)-21x-(7(4x-27)-63)=0

We add all the numbers together, and all the variables

-21x+3(3x-4)-(7(4x-27)-63)=0

We multiply parentheses

-21x+9x-(7(4x-27)-63)-12=0



We calculate terms in parentheses: -(7(4x-27)-63), so:

7(4x-27)-63

We multiply parentheses

28x-189-63

We add all the numbers together, and all the variables

28x-252

Back to the equation:

-(28x-252)



We add all the numbers together, and all the variables

-12x-(28x-252)-12=0

We get rid of parentheses

-12x-28x+252-12=0

We add all the numbers together, and all the variables

-40x+240=0

We move all terms containing x to the left, all other terms to the right

-40x=-240

x=-240/-40

x=+6

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