1/5(y-2)=1/10(y+6)

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Solution for 1/5(y-2)=1/10(y+6) equation: 



1/5(y-2)=1/10(y+6)

We move all terms to the left:

1/5(y-2)-(1/10(y+6))=0



Domain of the equation: 5(y-2)!=0

y∈R





Domain of the equation: 10(y+6))!=0

y∈R



We calculate fractions


(10yy/(5(y-2)*10(y+6)))+(-5yy/(5(y-2)*10(y+6)))=0



We calculate terms in parentheses: +(10yy/(5(y-2)*10(y+6))), so:

10yy/(5(y-2)*10(y+6))

We multiply all the terms by the denominator


10yy

Back to the equation:

+(10yy)





We calculate terms in parentheses: +(-5yy/(5(y-2)*10(y+6))), so:

-5yy/(5(y-2)*10(y+6))

We multiply all the terms by the denominator


-5yy

Back to the equation:

+(-5yy)



We get rid of parentheses

10yy-5yy=0

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