4-8+2(x-5)=12+6(4-2x)

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Solution for 4-8+2(x-5)=12+6(4-2x) equation: 



4-8+2(x-5)=12+6(4-2x)

We move all terms to the left:

4-8+2(x-5)-(12+6(4-2x))=0

We add all the numbers together, and all the variables

2(x-5)-(12+6(-2x+4))+4-8=0

We add all the numbers together, and all the variables

2(x-5)-(12+6(-2x+4))-4=0

We multiply parentheses

2x-(12+6(-2x+4))-10-4=0



We calculate terms in parentheses: -(12+6(-2x+4)), so:

12+6(-2x+4)

determiningTheFunctionDomain
6(-2x+4)+12

We multiply parentheses

-12x+24+12

We add all the numbers together, and all the variables

-12x+36

Back to the equation:

-(-12x+36)



We add all the numbers together, and all the variables

2x-(-12x+36)-14=0

We get rid of parentheses

2x+12x-36-14=0

We add all the numbers together, and all the variables

14x-50=0

We move all terms containing x to the left, all other terms to the right

14x=50

x=50/14

x=3+4/7

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