x/4=2/(x+2)

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Solution for x/4=2/(x+2) equation: 



x/4=2/(x+2)

We move all terms to the left:

x/4-(2/(x+2))=0



Domain of the equation: (x+2))!=0

x∈R



We calculate fractions


3x^2/4x+()/4x=0

We multiply all the terms by the denominator


3x^2+()=0

We add all the numbers together, and all the variables

3x^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$

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