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4+2(x-5)=2+6(4-2x)
We move all terms to the left:
4+2(x-5)-(2+6(4-2x))=0
We add all the numbers together, and all the variables
2(x-5)-(2+6(-2x+4))+4=0
We multiply parentheses
2x-(2+6(-2x+4))-10+4=0
We calculate terms in parentheses: -(2+6(-2x+4)), so:We add all the numbers together, and all the variables
2+6(-2x+4)
determiningTheFunctionDomain 6(-2x+4)+2
We multiply parentheses
-12x+24+2
We add all the numbers together, and all the variables
-12x+26
Back to the equation:
-(-12x+26)
2x-(-12x+26)-6=0
We get rid of parentheses
2x+12x-26-6=0
We add all the numbers together, and all the variables
14x-32=0
We move all terms containing x to the left, all other terms to the right
14x=32
x=32/14
x=2+2/7
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