3(2q+5)-4q=29

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Solution for 3(2q+5)-4q=29 equation: 



3(2q+5)-4q=29

We move all terms to the left:

3(2q+5)-4q-(29)=0

We add all the numbers together, and all the variables

-4q+3(2q+5)-29=0

We multiply parentheses

-4q+6q+15-29=0

We add all the numbers together, and all the variables

2q-14=0

We move all terms containing q to the left, all other terms to the right

2q=14

q=14/2

q=7

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