4(y+3)=2(y-1)

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Solution for 4(y+3)=2(y-1) equation: 



4(y+3)=2(y-1)

We move all terms to the left:

4(y+3)-(2(y-1))=0

We multiply parentheses

4y-(2(y-1))+12=0



We calculate terms in parentheses: -(2(y-1)), so:

2(y-1)

We multiply parentheses

2y-2

Back to the equation:

-(2y-2)



We get rid of parentheses

4y-2y+2+12=0

We add all the numbers together, and all the variables

2y+14=0

We move all terms containing y to the left, all other terms to the right

2y=-14

y=-14/2

y=-7

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