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5(y-3)=2(5-y)
We move all terms to the left:
5(y-3)-(2(5-y))=0
We add all the numbers together, and all the variables
5(y-3)-(2(-1y+5))=0
We multiply parentheses
5y-(2(-1y+5))-15=0
We calculate terms in parentheses: -(2(-1y+5)), so:We get rid of parentheses
2(-1y+5)
We multiply parentheses
-2y+10
Back to the equation:
-(-2y+10)
5y+2y-10-15=0
We add all the numbers together, and all the variables
7y-25=0
We move all terms containing y to the left, all other terms to the right
7y=25
y=25/7
y=3+4/7
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