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1/2(a-2)=1/3(a+3)
We move all terms to the left:
1/2(a-2)-(1/3(a+3))=0
Domain of the equation: 2(a-2)!=0
a∈R
Domain of the equation: 3(a+3))!=0We calculate fractions
a∈R
(3aa/(2(a-2)*3(a+3)))+(-2aa/(2(a-2)*3(a+3)))=0
We calculate terms in parentheses: +(3aa/(2(a-2)*3(a+3))), so:
3aa/(2(a-2)*3(a+3))
We multiply all the terms by the denominator
3aa
Back to the equation:
+(3aa)
We calculate terms in parentheses: +(-2aa/(2(a-2)*3(a+3))), so:We get rid of parentheses
-2aa/(2(a-2)*3(a+3))
We multiply all the terms by the denominator
-2aa
Back to the equation:
+(-2aa)
3aa-2aa=0
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