2/5(x+4)=1/4(2x-2)

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Solution for 2/5(x+4)=1/4(2x-2) equation: 



2/5(x+4)=1/4(2x-2)

We move all terms to the left:

2/5(x+4)-(1/4(2x-2))=0



Domain of the equation: 5(x+4)!=0

x∈R





Domain of the equation: 4(2x-2))!=0

x∈R



We calculate fractions


(8x2/(5(x+4)*4(2x-2)))+(-5xx/(5(x+4)*4(2x-2)))=0



We calculate terms in parentheses: +(8x2/(5(x+4)*4(2x-2))), so:

8x2/(5(x+4)*4(2x-2))

We multiply all the terms by the denominator


8x2

We add all the numbers together, and all the variables

8x^2

Back to the equation:

+(8x^2)





We calculate terms in parentheses: +(-5xx/(5(x+4)*4(2x-2))), so:

-5xx/(5(x+4)*4(2x-2))

We multiply all the terms by the denominator


-5xx

Back to the equation:

+(-5xx)



We get rid of parentheses

8x^2-5xx=0

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