6(y-3)=8(y-4)

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Solution for 6(y-3)=8(y-4) equation: 



6(y-3)=8(y-4)

We move all terms to the left:

6(y-3)-(8(y-4))=0

We multiply parentheses

6y-(8(y-4))-18=0



We calculate terms in parentheses: -(8(y-4)), so:

8(y-4)

We multiply parentheses

8y-32

Back to the equation:

-(8y-32)



We get rid of parentheses

6y-8y+32-18=0

We add all the numbers together, and all the variables

-2y+14=0

We move all terms containing y to the left, all other terms to the right

-2y=-14

y=-14/-2

y=+7

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