4(2-y)+1=2y+2-5(1-4y)

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Solution for 4(2-y)+1=2y+2-5(1-4y) equation: 



4(2-y)+1=2y+2-5(1-4y)

We move all terms to the left:

4(2-y)+1-(2y+2-5(1-4y))=0

We add all the numbers together, and all the variables

4(-1y+2)-(2y+2-5(-4y+1))+1=0

We multiply parentheses

-4y-(2y+2-5(-4y+1))+8+1=0



We calculate terms in parentheses: -(2y+2-5(-4y+1)), so:

2y+2-5(-4y+1)

determiningTheFunctionDomain
2y-5(-4y+1)+2

We multiply parentheses

2y+20y-5+2

We add all the numbers together, and all the variables

22y-3

Back to the equation:

-(22y-3)



We add all the numbers together, and all the variables

-4y-(22y-3)+9=0

We get rid of parentheses

-4y-22y+3+9=0

We add all the numbers together, and all the variables

-26y+12=0

We move all terms containing y to the left, all other terms to the right

-26y=-12

y=-12/-26

y=6/13

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