3(2d+4)-7(d+1)=3

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Solution for 3(2d+4)-7(d+1)=3 equation: 



3(2d+4)-7(d+1)=3

We move all terms to the left:

3(2d+4)-7(d+1)-(3)=0

We multiply parentheses

6d-7d+12-7-3=0

We add all the numbers together, and all the variables

-1d+2=0

We move all terms containing d to the left, all other terms to the right

-d=-2

d=-2/-1

d=+2

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