3(16c-15)-15=-c-11

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Solution for 3(16c-15)-15=-c-11 equation: 



3(16c-15)-15=-c-11

We move all terms to the left:

3(16c-15)-15-(-c-11)=0

We add all the numbers together, and all the variables

3(16c-15)-(-1c-11)-15=0

We multiply parentheses

48c-(-1c-11)-45-15=0

We get rid of parentheses

48c+1c+11-45-15=0

We add all the numbers together, and all the variables

49c-49=0

We move all terms containing c to the left, all other terms to the right

49c=49

c=49/49

c=1

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