3(y-5)+4(y+1)=5(2y-1)

Solution for 3(y-5)+4(y+1)=5(2y-1) equation:

3(y-5)+4(y+1)=5(2y-1)

We move all terms to the left:

3(y-5)+4(y+1)-(5(2y-1))=0

We multiply parentheses

3y+4y-(5(2y-1))-15+4=0


We calculate terms in parentheses: -(5(2y-1)), so:

5(2y-1)

We multiply parentheses

10y-5

Back to the equation:

-(10y-5)


We add all the numbers together, and all the variables

7y-(10y-5)-11=0

We get rid of parentheses

7y-10y+5-11=0

We add all the numbers together, and all the variables

-3y-6=0

We move all terms containing y to the left, all other terms to the right

-3y=6

y=6/-3

y=-2