1/5(8z-5)=-9/5z

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Solution for 1/5(8z-5)=-9/5z equation: 



1/5(8z-5)=-9/5z

We move all terms to the left:

1/5(8z-5)-(-9/5z)=0



Domain of the equation: 5(8z-5)!=0

z∈R





Domain of the equation: 5z)!=0

z!=0/1

z!=0

z∈R



We get rid of parentheses

1/5(8z-5)+9/5z=0

We calculate fractions


5z/(200z^2-125z)+(45z8/(200z^2-125z)=0



We calculate terms in parentheses: +(45z8/(200z^2-125z), so:

45z8/(200z^2-125z

We multiply all the terms by the denominator


45z8

We add all the numbers together, and all the variables

45z^8

We do not support ezpression: z^8

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